you are given the distance an object moves ( d ) while it experiences an acceler

Question

you are given the distance an object moves (d) while it experiences an acceleration (a). The initial velocty of the object was zero. You are then asked to find the final velocity of the object (vf).

How would you do this?

Question 4 options:

Use d = ½ at2 to find the time, t, it took to travel d, then use v = at to find vf.

Divide d by a to find the average velocity, vave, then use vave = vf /2 to find vf.

The answer cannot be found with the given information.

Find the initial velocity, vi, from vf = vi + at, then use vave = (vf – vi)/2 to find vf.

Calculate the time, t, it took to travel d by dividing a by d, then use v = ½ at to find vf.

Use d = ½ at2 to find the time, t, it took to travel d, then use v = at to find vf.

Divide d by a to find the average velocity, vave, then use vave = vf /2 to find vf.

The answer cannot be found with the given information.

Find the initial velocity, vi, from vf = vi + at, then use vave = (vf – vi)/2 to find vf.

Calculate the time, t, it took to travel d by dividing a by d, then use v = ½ at to find vf.

Explanation / Answer

V^2 = u^2+2*a*d

as given u = 0, so Vf = (2*a*d)^0.5

Use d = ½ at2 to find the time, t, it took to travel d, then use v = at to find vf

this is the only way we can find the final velocity

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