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(a) What is the x component of the electric force exerted by A on C? N (b) What

ID: 2003547 • Letter: #

Question

(a) What is the x component of the electric force exerted by A on C?
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(b) What is the y component of the force exerted by A on C?
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(c) Find the magnitude of the force exerted by B on C.
  N

(d) Calculate the x component of the force exerted by B on C.
  
Your response differs from the correct answer by more than 10%. Double check your calculations. N

(e) Calculate the y component of the force exerted by B on C.
  N

(f) Sum the two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C.
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(g) Similarly, find the y component of the resultant force vector acting on C.
  N

(h) Find the magnitude and direction of the resultant electric force acting on C.

magnitude N direction ° counterclockwise from the +x-axis

Explanation / Answer

a)

the electric force exerted by A on C = kq1q2/d^2 = 9*10^9*2.97*10^-4*1.04*10^-4/3^2 = 30.9 N

direction is +y axis

so the x component of the electric force exerted by A on C = 0

the y component of the electric force exerted by A on C = 30.9 N

the electric force exerted by B on C = kq2q3/d^2

here d = sqrt(3^2 + 4^2) = 5 m

the electric force exerted by B on C = 9*10^9*5.88*10^-4*1.04*10^-4/5^2 = 22.01 N

the x component of the electric force exerted by B on C = 22.01*sin(theta) = 22.01*(4/5) = 17.6 N

the y component of the electric force exerted by A on C = - 22.01*cos(theta) = 22.01*(3/5) = - 13.2 N

net electric force exerted on C = 17.6 i + 30.9 j - 13.2 j = 17.6 i + 17.7 j

mangnitude = sqrt(17.6^2 + 17.7^2) = 24.96 N

theta = arctan(17.7/17.6) = 45.16 deg

direction is 45.16 deg counterclockwise from the +x axis.