A student bikes to school by traveling first dN = 0.900 miles north, then dW = 0

Question

A student bikes to school by traveling first dN = 0.900 miles north, then dW = 0.500 miles west, and finally dS = 0.100 miles south.

You will now find the same quantity algebraically, without the need to use much geometry. Take the north direction as the positive y direction and east as positive x. The origin is still where the student starts biking.

Let d N be the displacement vector corresponding to the first leg of the student's trip. Express d N in component form.

Express your answer as two numbers separated by a comma (e.g., 1.0,2.0). By convention, thex component is written first.

Explanation / Answer

after the 1st movement, (0, 0.9)

after the 2nd movement, (-0.5, 0.9)

after the 3rd movement, (-0.5, 0.8)

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