<p>show the full work please . thank you in advance</p> <p>(1) What must the cha

Question

<p>show the full work please . thank you in advance</p>
<p>(1) What must the charge (sign and magnitude) of a particle of mass 1.50 g be for it to remain stationary when placed in a downward-directed electric field of magnitude 600 N/C?<br /><strong>Use 9.81 m/s^2 for the magnitude of the acceleration due to gravity.</strong></p>
<p>(2) <strong></strong>What is the magnitude of an electric field in which the electric force on a proton is equal in magnitude to its weight?</p>
<div class="partInstructions"><strong>Use <span>1.67&#215;10^&#8722;27</span>&#160;<img src="http://session.masteringphysics.com/render?units=kg" alt="kg" align="middle" /> for the mass of a proton, <span>1.60&#215;10^&#8722;19</span>&#160;<img src="http://session.masteringphysics.com/render?units=C" alt="C" align="middle" /> for the magnitude of the charge on an electron, and <span>9.81</span>&#160;<img src="http://session.masteringphysics.com/render?units=m%2Fs%5E2" alt="m/s^2" align="middle" /> for the magnitude of the acceleration due to gravity.</strong></div>

Explanation / Answer

(a) the force acting on charge q due to field E , F = Eq the force due to gravity , F = mg equating both equations , Eq = mg ----------- (1)      q = mg/E = 1.50*10^-3*9.81/600         = 2.45*10^-5 C the charge is -2.45*10^-5 C. (b) From equation ((1), E = mg/q = 1.67*10^-27*9.81/1.602*10^-19    = 10.22*10^-8 N/C

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