In an emergency stop to avoid an accident, a shoulder strap seatbelt holds a 54

Question

In an emergency stop to avoid an accident, a shoulder strap seatbelt holds a 54 kg passenger in place.

(pt. A) If the car was initially traveling at 86 km/h and came to a stop in 5.6 s along a straight, level road, what was the magnitude of the average force applied to the passenger by the seatbelt?

(pt. B) What was the direction of the average force applied to the passenger by the seatbelt? (a) the same as the motion or the velocity, (b) opposite to the motion or the velocity, or (c) perpendicular to the motion or the velocity

Explanation / Answer

Mass, m = 54 kg Initial speed, vi = 86 kmph                         = 86 * (5/18) m/s                         = 23.89 m/s Final speed, vf = 0 m/s Time, t = 5.6 s (a) Acceleration, a = ( vf - vi ) / t                         = ( 0 - 23.89 ) / 5.6                         = - 4.27 m/s^2 Force, F = m a               = 54 * - 4.27               = -230.36 N Here, '-' sign implies that the force is retardation force. Magnitude of the force = 230.36 N (b) Direction: Option - b--> Opposite to motion or velocity

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