http://session.masteringphysics.com/problemAsset/1042462/3/YF-26-32.jpg The resi

Question

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The resistance of the coil of a pivoted-coil galvanometer is 8.46 , and a current of 2.70×102 causes it to deflect full scale. We want to convert this galvanometer to an ammeter reading 19.0 full scale. The only shunt available has a resistance of 2.50×102
What resistance, R, must be connected in series with the coil (see the figure )?


Tried to set up the problem ----> (current of galvanometer at fullscale deflect)*(Resistance of galvanometer) = (ammeter reading fullscale)*(1/.0250A + 1/R)^-1

After plugging in the number and trying to solve for R, I came up with 0.0120A for the resistor connected in series. No idea if my theory is correct or not but answer is definitely wrong!

Explanation / Answer

to solve, I used: i_fs*(Rcoil-Rseries) = (i_ammeter - i_g)*(i_fs) plug in values and solve for Rseries ---> Rseries = 9.11ohms

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