a.)A long straight wire carries a 2.00-A current. What is the magnetic field 5.0

Question

a.)A long straight wire carries a 2.00-A current. What is the magnetic field 5.0 cm from this wire? 0 = 4 x 10-7 Tm / A
.8 x 10-5 T


b.) Suppose the wire is cut and fashioned into a single circular current loop 10.0 cm in diameter carries a 2.00-A current. What is the magnetic field at the center of this loop?

2.5 x 10-5 T


c.)Suppose that 1000 of these loops are connected in series within a 500 cm length to make a solenoid 500 cm long. What is the magnetic field at the center of this solenoid?


d.)Is it 1000 times the field at the center of the single loop? Explain why or why not.


e.)Two identical parallel wires that carry currents of 8 A and 12 A respectively in opposite directions are separated by a distance of 5 cm. Calculate the force per unit length on the wires. Is the force attractive or repulsive?

Explanation / Answer

(a) magnetic field due to a straight current carrying wire B =   0I / 2r 0 = 4 x 10-7 T.m / A Here I = current = 2.00A r = radius of the loop   =   0.05 m B = 0.80*10^-5 T ---------------- (2) magnetic field at the centre of the loop B = 0I / 2r    Here I = 2.00A   ,   radius of the loop r =   0.05 m B=2.51*10^-5 T ----------------------------------- (3) magnetic field due to solenoid B' = 0 n I Here   n = N /l   =   number of turns / l   = 1000 / 5.0 m   = 200 B   =   5.024*10^-4 T (4)  B'   / B    =  5.024*10^-4 T    /  2.51*10^-5 T    = 20.01 magnetic field due to solenoid   is 20.01 times greater than magnetic field at the centre of the loop (e) Force per unit length between the two parallel wires F = 0 I1 * I2    / 2r F =   ..............N Here r = distance between the two wires since the current are in opposite directions the two wires are repel with each other

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