An 90.0 kg skydiver jumps out of a balloon at an altitude of 1 400 m and opens t

Question

An 90.0 kg skydiver jumps out of a balloon at an altitude of 1 400 m and opens the parachute at an altitude of 160 m.
(a) Assuming that the total retarding force on the diver is constant at 65.0 N with the parachute closed and constant at 3 600 N with the parachute open, what is the speed of the diver when he lands on the ground? m/s
(b) Do you think the sky diver will be injured? Explain.
(c) At what height should the parachute be opened so that the final speed of the skydiver when he hits the ground is 5.00 m/s?m
(d) How realistic is the assumption that the total retarding force is constant? Explain your answer.

Explanation / Answer

by conservation of energy we have the kinetic energy of the diver when he reaches ground as m*g*1400-65*(1400-160)-3600*160=.5*m*v*v solve for v=113.38m/sec. b)he will get injured c)m*g*1400-65*1400-0.5*m*25/(3600-160)=332.17m d)yes it is sensible assumption because the drag force becomes constant once the terminal velocity is reached.

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