A beam of laser light with wavelength 612 nm is directed through a slab of glass

Question

A beam of laser light with wavelength 612 nm is directed through a slab of glass having index of refraction 1.55.
(a) For what minimum incident angle would a ray of light undergo total internal reflection?

(b) If a layer of water is placed over the glass, what is the minimum angle of incidence on the glass-water interface that will result in total internal reflection at the water-air interface? (The beam of light is directed upward through the slab of glass, through the layer of water, and experiences total internal reflection at the water-air interface on top.)

I do not understand how to do this problem. Please help!

Explanation / Answer

a) Given that index of refraction of slab is n=1.55 if i is the minimum angle of incidence for which the total internal reflction is observed then sin i=1/n            i=sin-1(1/1.55)             =sin-1(0.6451)            =40.173 deg b) index of refraction of water is n=1.33 if i is the minimum angle of incidence for which the total internal reflction is observed then sin i=1/n            i=sin-1(1/1.33)             =sin-1(0.7518)            =48.746deg b) index of refraction of water is n=1.33 if i is the minimum angle of incidence for which the total internal reflction is observed then sin i=1/n            i=sin-1(1/1.33)             =sin-1(0.7518)            =48.746deg if i is the minimum angle of incidence for which the total internal reflction is observed then sin i=1/n            i=sin-1(1/1.33)             =sin-1(0.7518)            =48.746deg

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