Consider 3 resistors: 10 K ohms, 20 k ohms, and 30 k ohms 1. Calculate the total

Question

Consider 3 resistors: 10 K ohms, 20 k ohms, and 30 k ohms

1. Calculate the total resistance if these resistors are connected in series.
60 k ohms?
2. Calculate the total resistance if these resistors are connected in parallel
5.45 k ohms?
Let network A consist of the 3 resistors above connected in series and network B consist of the 3 resistors connected in parallel.
If each network were in turn connected to a 9 volt battery, in which case would there be a greater amount of current through the battery? Explain how you can use your results from parts 1 and 2 to support your answer.

Explanation / Answer

The current is a flow of electrons in a network which depends upon the resitance of the network. The voltage applied to a network is a drive force.

   I is proportional to V as per ohms law, when tempararature is constant.

V=RI, where R is the resistance.

1) Network A : The equivalent resitance value is 60K

2) Network B : The equivalent  resitance value is 4.54K

When applied voltage is same for both the networks, The current value depends upon the resistance.

The resistance is a opposite force, hence the current will be larger for a smaller resistance value.

Hence Network B has greater current compared to Network A

Also the current values are Network A : 9 v/60K = 0.15mA

   The current values are Network B : 9 v/4.54K =1.982mA

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