The drawing shows light incident on a polarizer whose transmission axis is paral

Question

The drawing shows light incident on a polarizer whose transmission axis is parallel to the z axis. The polarizer is rotated clockwise through an angle . The average intensity of the incident light is 8.5 W/m2. Determine the average intensity of the transmitted light for each of the six cases.

Intensity of Transmitted Light Intensity of Transmitted Light Incident Light = 0° = 35° Unpolarized   ---Select--- W W/m^2 N J/m3 J   ---Select--- W/m^2 J/m3 W J N Polarized parallel to z axis   ---Select--- W N J W/m^2 J/m3   ---Select--- W/m^2 J W N J/m3 Polarized parallel to y axis   ---Select--- N J W/m^2 W J/m3   ---Select--- W/m^2 J N W J/m3

Explanation / Answer

The intensity of the incident ligth I0 = 8.5 W/m^2 Here the trasmission axis is parallel to the z-axis When an unpolarized ligth passing through polarizer then the transmitted light intensity is should be half of the incident light what ever the angle ie., = 0deg or 35deg it may incident    therefore the intensity of the transmitted light                 I = 8.5/2 = 4.25 W/m^2 (b) Polarized parallel to the z-axis         When the ligth incident parallel to z-axis =0 then the transmitted ligth intensity            I = I0cos^2              = 8.5 W/m^2 (c) When the ligth is incident parallel to the y-axis then the angle between them = 90 therefore the intensity of the transmitted ligth             I = I0 cos^2               = 0 when the angle = 35 deg then the angle between them is 90-35 = 55 deg therefore the intensity of the transmitted ligth             I = I0 cos^2 therefore the intensity of the transmitted ligth             I = I0 cos^2               = (8.5)cos^2(55)               = 2.8 W/m^2

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