If the electric field magnitude in t he conductor is 1.28 V/m. what is the total

Question

If the electric field magnitude in t he conductor is 1.28 V/m. what is the total current? If the material lias 8.5 times 1028 electrons per cubic meter. find the average drift speed. In Figure 4. the terminal voltage of the 12 V battery is 10.2 V. Determine the internal resistance r of the battery, the resistance of R of the circuit. the rate at which electrical energy is dissipated in the battery, and the rate at which electrical energy is dissipated in the external resistor. Bonus: A swimmer is in a water at a distance d = 35.0 m from a point where a lightning of current 78000 A strikes the water. The water has a resistivity of 30 Ohm m. The width of the swimmer(from shoulder to shoulder in a vertical position) along the radial line from the strike is 0.70 m and his resistance across the width is -1000 Ohm. Assume that the current spreads through the water over a hemisphere centered on the strike point What is the current through the swimmer? Is it fatal?

Explanation / Answer

(a) terminal voltage    =   V - Ir   Here   given = 10.2 V    , V =   12 V   , current  I = 1.5 A internal resistance r = ( 12 - 10.2 )V / 1.5 A   = 1.2 --------------------------------------------------------- (b) Voltage across the resistor   = IR exterior resistance   R   = / I   = 10.2 V / 1.5A = 6.8 --------------------------------------------------------------- (c)rate of energy dissipated in the battery    =   I^2 *r   =   ( 1.5A)^2 * (1.2)   = 2.7 w ---------------------------------------------- (d) rate of energy dissipated in the resistor R             = I^2 *R   = (  ( 1.5A)^2 * (6.8) ) = 15.3 w for remainig please post as another questions

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