A Nichrome wire 75cm long and .25mm in diameter is connected to a 1.7 volt flash

Question

A Nichrome wire 75cm long and .25mm in diameter is connected to a 1.7 volt flashlight battery.

A) What is the electric field inside the wire?
B) Next the Nichrome wire is replaced by a wire of the same length and diameter, and same mobile electron density but with electron mobility 4 times as large as that of Nichrome. Now what is the electric field inside the wire?
C) The electron current in the first circut (Nichrome) is i1. The electron current in the second circut (wire with higher mobility) is i2. Which of the following statements is true?

1)i2=i1

2)i2<i1

3)i2>i1

4) not enough information to compare the two currents

Explanation / Answer

A.) Using the Biot-Savart law which relates magnetic field to current. Electric field 75cm = .75m E = V/L = 1.7/0.75 = 2.26667 B.) I think the electric field is the same C.) not sure sorry, but Id say 1.

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