A magnetic field exerts a torque on each of the current-carrying double loops. T
ID: 2011118 • Letter: A
Question
A magnetic field exerts a torque on each of the current-carrying double loops. The loops lay in xy-plane, each carry the same current I and the uniform magnetic field points to positive x-direction. Calculate the torques for each of the current loops.
So far this is what i have:
= BIAN sin and = IAN
the first loop was a rectangle and I already calculated the area which is 6m2
second loop is a trapezoid and the area is 8m2
third loop is a triangle and the area is 3 m2
now since they all have the same B, I, and N would the total torque be just the areas of the loops?
(because there are no other given values)
Explanation / Answer
Reason: Acc. to ur given data , the values of B , N , I are not changes for all Geomertc shapes of the Loops As Areas of the loops alonely changed. The torque acting on them is given by the formula as : Torque acting on the rectangular coil: 1 = B N I x 6 (since Area of the recatngualar:A = 6m2) Torque acting on the Trapezoid is : 2 = BNI x 8 Torque acting on the Traingle is : 3 = BNI x 3 Thus, Total torque acting on all the loops is : = 1 + 2+ 3 = BNI (6 + 8 + 3 ) = BNI (1 7) Note: If B , N , I values are Knowns we can calculate the torque acting on all the Loops Note: If B , N , I values are Knowns we can calculate the torque acting on all the LoopsRelated Questions
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