1 ) A source of sound waves of frequency 0.9 kHz is traveling through the air at
ID: 2011448 • Letter: 1
Question
1 ) A source of sound waves of frequency 0.9 kHz is traveling through the air at 0.75 times the speed of sound.(a) What is the frequency of the sound received by a stationary observer if the source moves toward her? unit in kHZ
(b) Now, the source moves away from the stationary observer. What is the frequency of the sound received in this case? unit in KHZ
2 ) Steel railroad tracks of length L = 18.20 m are laid at 10.0° C. How much space should be left between the track sections if they are to just touch when the temperature is T = 49.5° C?
Explanation / Answer
given that frequency ofsource of sound n = 0.9 kHz speed of sound Vs = 0.75Va)APPARENT FREQUENCY=(v-vo)n/(v-vs)=(v-0)0.9/v-0.75v=3.6kHz
b)APPARENTFREQUENCY=(v-vo)n/(v+vs)=(v-0)0.9/v+0.75v=0.51kHz
2) Given that Steel railroad tracks of length (l0) =18.20 m The initial temperature is (T1)=100C The final temperature is (T2) =49.50C Coefficient of linear expanison of the steel () =12*10-6K-1 We know that the definition of coefficient of linearexpansion, The space left between the tracks is l = lot = (12*10-6K-1)(18.20m)(39.50C) =0.008626m =8.626mm Given that Steel railroad tracks of length (l0) =18.20 m The initial temperature is (T1)=100C The final temperature is (T2) =49.50C Coefficient of linear expanison of the steel () =12*10-6K-1 We know that the definition of coefficient of linearexpansion, The space left between the tracks is l = lot = (12*10-6K-1)(18.20m)(39.50C) =0.008626m =8.626mm We know that the definition of coefficient of linearexpansion, The space left between the tracks is l = lot = (12*10-6K-1)(18.20m)(39.50C) =0.008626m =8.626mm
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