this solution is given: The difference in time for two pulse (t) = 1.27x10-7 s.

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this solution is given:

The difference in time for two pulse (t) = 1.27x10-7 s.
Speed of light (c) = 3.0 x 108m/s
Each pulse emitted (tpulse) = 0.450 s

The distance travelled by the speeding vehicle between two pulses
d = 0.5ct
Now the speed of the vehicle
v = d / tpulse
= 0.5ct / tpulse
= 0.5(3 x 108m/s)( 1.27x10-7 s) / 0.450 s
= 42.3m/s
I want to know how they determined that the distance traveled by the speeding car is .5 c t.... Will you please give me a detailed explanation of this and the remainder of the problem?

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