Note: a very similar problem is found in the textbook I linked, but in the probl

Question

Note: a very similar problem is found in the textbook I linked, but in the problem I'm given and asking about here, the magnetic field B is directed OUT of the paper (i.e. dots instead of x's)

The drawing shows that a uniform magnetic field is directed perpendicularly out of the plane of the paper and fills the entire region to the left of the y axis. There is no magnetic field to the right of the y axis. A rigid right triangle ABC is made of copper wire. The triangle rotates counterclockwise about the origin at point C. What is the direction (clockwise or counterclockwise) of the induced current when the triangle is crossing (a) the +y axis, (b) the x axis, (c) the y axis, and (d) the +x axis? For each case, justify your answer.

Explanation / Answer

When the triangle is crossing the +y axis, the magnetic flux through the loop is increasing since it is entering the field. To counter this the induced field will be in the direction opposite of the field. Using the right hand rule, the current will be in clockwise direction.

When the triangle is crossing the -x axis there is no change in the magnetic flux within the wire loop therefore there will be no induced current.

When the triangle is crossing the -y axis, the magnetic flux through the loop is decreasing since it is exiting the field. To counter this the induced field will be in the direction of the field. Using the right hand rule, the current will be in counter-clockwise direction

Again when the triangle is crossing the +x axis there is no change in the magnetic flux through the loop of wire so no induced current.

Hope this help!

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