Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Consider a Bohr model of doubly ionized lithium. (a) Write an expression similar

ID: 2016554 • Letter: C

Question

Consider a Bohr model of doubly ionized lithium.

(a) Write an expression similar to En = -13.6 eV/n^2 ? E2 = -13.6 eV/2^2 = -3.40 eV for the energy levels of the sole remaining electron. (Use the following as necessary: n.)
En =_______eV

^no clue what this questions asking..

(b) Find the energy corresponding to n = 5.

________
(c) Find the energy corresponding to n = 2.

________
(d) Calculate the energy of the photon emitted when the electron transits from the fifth energy level to the second energy level. Express the answer both in electron volts and in joules.
_______eV
_______J

(e) Find the frequency and wavelength of the emitted photon.
_____Hz
_____nm

(f) In what part of the spectrum is the emitted light?
ultraviolet region
gamma ray region
visible light region
infrared region
x-ray region

Explanation / Answer

       (a)    For lithium   aromic  number z = 3           Energy    E n   = - 13.6 *z2   / n2 (b)    For    n   = 5    and z = 3        E5    = -13.6 eV   * 32   / 52     =    -4.896   eV (c) for    n = 2 and   Z   = 3              E2   =    - 30.6 eV (d)    Energy of the photon   when    5 --> 2 is    E    = E5   - E2      =      -    - 30.6 eV   - (- 4.896 eV)       = 25.704 eV    in Joules     E   = ( 25.704 eV ) ( 1.6*10-19 J   / eV)   =   41.12**10-19 J (e)   frequency   f    = E / h                                    =   41.12**10-19 J    /   ( 6.63*10-34 J.s)   =    6.2*1015 Hz wavelength       =   c / f   = ( 3*108 m/s ) /  ( 6.2*1015 Hz  )   =   0.48*10-7 m             = 48 nm (f) ultraviolet region
   in Joules     E   = ( 25.704 eV ) ( 1.6*10-19 J   / eV)   =   41.12**10-19 J (e)   frequency   f    = E / h                                    =   41.12**10-19 J    /   ( 6.63*10-34 J.s)   =    6.2*1015 Hz wavelength       =   c / f   = ( 3*108 m/s ) /  ( 6.2*1015 Hz  )   =   0.48*10-7 m             = 48 nm (f) ultraviolet region
Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote