Question 1: An object is placed a distance d in front of a concave mirror with a

Question

Question 1: An object is placed a distance d in front of a concave mirror with a radius of curvature r = 12 cm. The image formed has a magnification of M = 3.5.
a) Write an expression for the objects distance, D.
b) Numerically, what is the distance?

Question 2: A candle (h = 0.22 m) is placed to the left of a diverging lens (f = -0.053 m). The candle is d = 0.14 m to the left of the lens.
a) Write an expression for the images distance, di.
b) Numerically, what is this distance?
c) Is this real or virtual?
d) Numerically, what is the images height, hi?

Explanation / Answer

a)Given that radius of curvature is R=12cm hence the focal length f=R/2=6cm magnification M=3.5 if p is the object distance and q is the image distance then 1/p+1/q=1/f but M=-q/p       q=-Mp=-3.5p so 1/p-1/3.5p=1/f f=1.4p p=f/1.4 =4.28cm and the image distance is q=-15cm As per cramster there should be only one Question per post so please post other question seperately As per cramster there should be only one Question per post so please post other question seperately

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