1) A mass of 1.50 kg is attached to a spring and the system is undergoing simple
ID: 2018071 • Letter: 1
Question
1) A mass of 1.50 kg is attached to a spring and the system is undergoing simple harmonic oscillations with a frequency of 3.55 Hz and an amplitude of 10.0 cm. What is the speed of the mass when it is at 3.60 cm from its equilibrium position?
the answer is 2.08, but i dont know how to get it can you explained?
2) The amplitude of a 3.00-kg object in simple harmonic motion is 0.52 m. The maximum acceleration of the object is 4.3 m/s2. What is the period of the simple harmonic motion? Give your answer in SI units.
the answer is 2.2. can you show me the steps?
Explanation / Answer
Data: Mass, m = 1.50 kg Frequency, f = 3.55 Hz Amplitude, A = 0.1 m Distance, x = 0.036 m Solution: (a) Speed, v = [ A^2 - x^2 ] = (2f) [ A^2 - x^2 ] = ( 2 * 3.55 ) [ 0.1^2 - 0.036^2 ] = 2.08 m/s Ans: Speed, v = 2.08 m/s (b) amax = 4.3 m/s^2 Mass, m = 3 kg Amplitude, A = 0.52 m amax = ^2 A 4.3 / 0.52 = ^2 ^2 = 8.27 4^2 / T^2 = 8.27 T^2 = 4^2 / 8.27 T = 2 / 8.27 = 2.2 s Ans: Time period, T = 2.2 sRelated Questions
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