In each figure below, the magnetic field strength is 0.50 T. A-15 nC charge is t

Question

In each figure below, the magnetic field strength is 0.50 T. A-15 nC charge is travelling with a speed of 5.0 m / s. Determine the magnitude and direction of the magnetic force. The magnetic field is directed into the page A 45 nC charge is traveling with a speed of 7.5 m / s. Determine the magnitude and direction of the magnetic force. A 5.3 mA current runs through the wire as shown. Determine the magnitude and direction of the magnetic force along 12 cm of the wire. Assume the magnetic field is constant throughout the 12 cm of the wire.

Explanation / Answer

 Given that magnetic field strength is  B  = 0.50 T  charge is  q  = -15.0n C  speed of the charge is v  = 5.0 m/s   magnetic force is  F  = q v * B sin                                  = - 15.0 *10^-9 C * 5.0 m/s * 0.5 sin 30                                 = 18.75 *10^-9 N         direction is - z axis b)  Given that charge is  q  = 4.5 *10^-9 C   speed is  v  = 7.5 m/s     magnetic force is  F = q v B                                  = 4.5*10^-9 C * 7.5 m/s *0.5 T                                 = 16.8*10^-9 N                        direction - x axis  c ) current in the wire is   i  = 5.3 *10^-3 A  , length of the wire is  L  = 12.0*10^-2 m         magnetic force is F  = i L B                                   = 5.3 *10^-3 A * 12.0*10^-2 m * 0.5 T                                   = 3.18*10^-4 N                    direction is z axis

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