An object 2cm high is placed 4cm in front of a divergent lens of local length 8

Question

An object 2cm high is placed 4cm in front of a divergent lens of local length 8 cm. A concave mirror is placed 5 cm behind the lens and has a radius of curvature of 12 cm. Find the location of the first image formed and describe it (orientation, size, real or virtual) sketch of principle rays required for this image. Find the location of (he second image formed and describe it (orientation, size, real or virtual) Find the location of the third image formed and describe it (orientation, size. real or virtual)

Explanation / Answer

   Let , object distance from the first lens = u1 = 4 cm = 0.04 m focla lenght of the divrgent lens = f1 = 8 cm = 0.08 m Let , image formed by th e first lens at adistnce = v1 = ? It is known by t he formula 1/ f = 1/ u1 + 1/ v1 v1 = f u1 / u1 -f       = (0.08)(0.04)/(0.08-0.04)       = 0.08 m or 8 cm Image is virtual and erected Now , this image distanc is acts as a object distnce for second lens Let , v2 be the image distnce for second lens v2 = 8 cm = 5 cm = 3 cm = 0. 03 m = u2 Since , radious of curvaure of the second lens is R = 12 cm focal length of the second lens is : f2 = R /2 = 6 cm = 0. 06 m thus, v2 = u2 f2 / u2 - f2        = (0.03)(0.06) / (0.03-0.06)        = -0.06 or   - 6 cm

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