a) a copper vessel of mass 1000gm contains 500 gm of water at 50 degree celsius.

Question

a) a copper vessel of mass 1000gm contains 500 gm of water at 50 degree celsius. an ice cube of mass 100 gm at temperature -30 degree celcius is dropped into this vessel. what is the final temperature.
b) if at the same time as dropping the ice cube, we also drop in a 200gm piece of glass at a temperature of 110 degree celsius. what is the final temperature

given values
specific heat in cal/gm per degree celsius
ice .5 water 1.0 copper 0.1 glass 0.2
latent heat of water vaporization 540cal/gm and fusion 80 cal/gm

Explanation / Answer

a) [(m*cp*dt)_cu] + [(m*cp*dt)_water] = [(m*cp*dt)_ice] + [(m*Lf)_ice] + [(m*cp*dt)_water] [1000*0.1*(50-T)] + [500*1*(50-T)] = [100*0.5*(0-(-30))] + [100*80] + [100*0.5*(T-30)] 5000-100T+25000-500T = 1500+8000+50T-1500 T = 33.846 C b) [(m*cp*dt)_cu] + [(m*cp*dt)_water] + [(m*cp*dt)_glass] = [(m*cp*dt)_ice] + [(m*Lf)_ice] + [(m*cp*dt)_water] [1000*0.1*(50-T)] + [500*1*(50-T)] + [200*0.2*(110-T)] = [100*0.5*(0-(-30))] + [100*80] + [100*0.5*(T-30)] 15000-100T+25000-500T+4400-40T = 1500+8000+50T-1500 T = 52.75 C

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