part 1. A 0.095kg aluminium sphere is dropped from the roof of a 40m -high build

Question

part 1.
A 0.095kg aluminium sphere is dropped from the roof of a 40m -high building.If 69% of the thermal energy produced when it hits the ground is absorbed by the sphere, what is its temperature increase?
delta T = .... in degress in celcius

part 2.
A soft-drink can contains about 0.43kg of liquid at 8 degrees C. Drinking this liquid can actually consume some of the fat in the body, since energy is needed to warm the water to body temperature (37 Degrees C).How many food Calories should the drink have so that it is in perfect balance with the heat needed to warm the liquid?
Q= .... C degrees

Explanation / Answer

Given that The mass of aluminium, m = 0.095 kg = 95 g The height of the roof, h = 40 m We have a formula for the heat energy as          Q = msT Since the mass is dropped from certain height, the potential energy is nothing but the heat energy. So, Q = mgh From the above two equations we have           msT = mgh                T = gh/s = 9.8*40/0.9      ( specific heat of aluminum s = 0.9 J/kg k)                    = 435.6 K Now, 69% of thermal energy is given by = 435.6 * (69/100) = 300.5 K = 27.5 deg C please given the next problem as separate post. ThanQ

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