Part A Part B Part C Part D Part E Part F Some atomic masses Part A Calculate th

Question

Part A Part B Part C Part D Part E Part F Some atomic masses Part A Calculate the mass defect of the nitrogen nucleus {}^{14}_{ 7}{rm N}. The mass M_{rm N} of neutral {}^{14}_{ 7} {rm N} is equal to 14.003074 atomic mass units. Part B Calculate the binding energy E_B of the nitrogen nucleus {}^{14}_{ 7}{rm N}. Part C Calculate the binding energy per nucleon of the nitrogen nucleus {}_{ 7}^{14}{rm N}. Part D Calculate the mass defect of the helium nucleus {}^{4}_{2}{rm He}. The mass of neutral {}^4_2 {rm He} is given by M_{rm He}=4.002603;rm u. Part E Calculate the binding energy E_B of the helium nucleus {}^{4}_{2}{rm He}. Part F Calculate the binding energy per nucleon of the helium nucleus {}^{4}_{2}{rm He}.

Explanation / Answer

The mass defect is the difference in mass between the atomic species and the sum of the constituent particles that make up the species. A) In the case of Nitrogen-14: mass defect = 7*(m_electron + m_proton + m_neutron) - 14.003074 The binding energy of the nucleus is the mass defect converted to energy by: E = m c^2. Be careful what units you want to be in in the end, as you may have to make some conversions. C) To find the binding energy per nucleon, divide the binding energy by the total number of nucleons (in this case 14). D) See A above for description. In the case of Helium-4: mass defect = 2*(m_electron + m_proton + m_neutron) - 4.002603 E) See B above for description. Use the equation E = m c^2, where m is the mass defect. F) Same as in C except the number of nucleons is 4.

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