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Zirconium has an HCP crystal structure and a density of 6.51 g/cm3. What is the

ID: 2021692 • Letter: Z

Question

Zirconium has an HCP crystal structure and a density of 6.51 g/cm3. What is the volume of its unit cell in cubic meters? If the c/a ratio is 1.593, compute the values of c and a.

Explanation / Answer

There are 6 atoms in the hcp unit cell. So mass of the unit cell = 91.224*6 =547.34400amu Now the density = 6.51g/cm^3 Now 1 gm =6.0221415 × 10^23 V = mass/density => 547.34/(6.51* 6.0221415 × 10^23) = 1.39612802 × 10^-22 cm^3 = 1.396 × 10^-28 m^3 2)c/a = 1.593 Hint: use the fact that base of HCP is a hexagon and the height = c =1.593a. now calculate the volume by using this and compare the value given in part A You will get a & c To calculate the volume use V =area of base *height to calculate the area of base treat base to be made of 6 equilateral trainge