A skier of mass 59 kg skis straight down a 13° slope at constant velocity. Draw

Question

A skier of mass 59 kg skis straight down a 13° slope at constant velocity. Draw a free-body diagram of the skier with the various external forces acting on her. Include the force of air resistance, which is directed opposite the velocity. (Do this on paper. Your instructor may ask you to turn in this work.)
(a) Find the value of the normal force.
130.199N- this is incorrect

(b) The force of air resistance has a magnitude of 73 N. Find the frictional force on the skis.


(c) What is the coefficient of kinetic friction?

Explanation / Answer

a. Fn = mgcos(theta) = 59(9.8)cos(13)= 563.38 N b. F up = F down F of air resistance + Ff = Fg 73 + Ff = 59(9.8)sin(13) Ff= 57.066 N c. Ff= 57.066 = umgcos(theta) = u(59)9.8cos(13) u=.1012 Hope this helps! Rate lifesaver :)

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