1. In Kumquat trees, plant height is determined by 3 genes as in our simplified
ID: 202228 • Letter: 1
Question
1. In Kumquat trees, plant height is determined by 3 genes as in our simplified model of polygenic inheritance. Each locus has a contributing allele and a non-contributing allele. A tree with the genotype AABBCC grows to be 100cm tall. The other homozygote grows to be 40cm tall. What is the contribution for each contributing.allele? a. 60cm b.50cm c. 30cm d. 20cm e. 10cm 1. 2. If you crossed a 100cm tree with a 40cm tree and then crossed the F, to get the F generation, what proportion of the F2 offspring will grow to be 70cm tall? e. 1/8 b. 20/64 c. 20/128 d. 10/64 Considering again the F2 produced in question 2, what proportion of the offspring will be 70cm tall or taller? 3. b. 15/64 c. 6/64 d. 42/64 e. 1/64Explanation / Answer
1) 10 cm - Each locus should be contributing 20cm and the dominant allele should be contributing 10cm, because the other homozygote tree is 40 cm tall.
2) 20/64 - Atleast three dominant alleles need to be present in a genotype to produce 70cm tree. When crossing F1 heterozygous, 20 offsprings of the 64 total offsprings will be od 70cm tall.
3) 42/64 - As mentioned above atleast three dominant allleles are needed to be present in 70cm or a taller tree. So, in F2 generation 42 out of 64 offspring will be 70cm or taller.
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.