Note: The currents are not necessarily in the direction shown. Use the following
ID: 2023172 • Letter: N
Question
Note: The currents are not necessarily in the direction shown. Use the following variables as necessary: V1 = 23.0 V, V2 = 15.0V, and R = 8.0.
(No Response) W
I'm stuck... what am I doing wrong? Any help is appreciated.
I1 .508 A I2 .558Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error.A I3 1.097
Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error.A
Explanation / Answer
using matrices:[40I1,-12I2]
[-12I1,20I2],[23-15=8;15]=0.5183 amps I1, 1.0609 amps I2
1.0609+0.5183=1.5792 amps I3
a) current in 28 is 0.5183 amps
current in 12 is 1.0609 amps
current in 8 is 1.5792 amps
b) power dissipated in 28 is I2*R7.522 W
power dissipated in 12 is 1.06092*1213.51 W
power dissipated in 8 is1.57922*819.951 W
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