Atwood\'s machine, in which two containers are connected by a cord (of negligibl
ID: 2023994 • Letter: A
Question
Atwood's machine, in which two containers are connected by a cord (of negligible mass) passing over a frictionless pulley (also of negligible mass). At time t = 0 container 1 has m1 and container 2 has mass m2 with m1 < m2, but container 1 is losing mass (through a leak) at the constant rate r. (a) At what rate is the magnitude of acceleration of the containers changing at time t? (b) When will container 2 reach maximum acceleration? Express your answers in terms of the variables given and g.
Explanation / Answer
m2g-T = m2*a
T-m1g = m1*a
a=(m2-m1)g/(m1+m2)
given dm1/dt = -r
da/dt = g{-(m1+m2)(-r)-(m2-m1)(-r)/(m1+m2)^2}
= 2*gr*m2 / (m1+m2)2
so the accelaration will reach maximum at t = m1/r when container m1 becomes empty
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