A patient can\'t see objects closer than 48.6 cm and wishes to clearly see objec

Question

A patient can't see objects closer than 48.6 cm and wishes to clearly see objects that are 20.3 cm from his eye.
(a) Is the patient nearsighted or farsighted?
nearsighted
farsighted



(b) If the eye-lens distance is 1.99 cm, what is the minimum object distance p from the lens?
cm

(c) What image position with respect to the lens will allow the patient to see the object?
cm

(d) Is the image real or virtual? Is the image distance q positive or negative?
real image
distance is negative
distance is positive
virtual image



(e) Calculate the required focal length.
cm

(f) Find the power of the lens in diopters.
diopters

(g) If a contact lens is to be prescribed instead, find p, q, and f, and the power of the lens.
p = cm
q = cm
f = cm
P = diopters

Explanation / Answer

(a) Farsighted (b) 18.31 cm (c) 46.61 cm (d) Virtual Image; Distance Is Negative (e) 30.2 cm (f) 3.32 diopters (g) p = 20.3 cm q = -48.6 cm f = 34.9 cm P = 2.87 diopters

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