a) Find the magnetic force on an electron moving with a speed of 10^6 m/s northw
ID: 2026797 • Letter: A
Question
a) Find the magnetic force on an electron moving with a speed of 10^6 m/s northward at a position where the magnetic field of the earth has a size of 0.5 * 10^-4 T and is directed 45 degrees north of west. Compare your answer o the weight of the electron.
b) Find the magnetic force on a proton moving wih a speed of 10^6 m/s northward at a position where the magnetic field of the eart h has size 0.5 ^ 10^-4 T and is directed 45 degrees south of west. Compare your answer to the weight of the proton.
Explanation / Answer
a) The magnetic force on the electron = q(VxB)
= qvb sin
= 1.6*10^9*10^6* 0.5 * 10^-4(sin 45)
=5.65*10^10 Newton along upward direction.
The ratio of this force to the weight of the electron = 5.65*10^10/9.11*10^-31 *9.8 =0.0632*10^41
The magnetic force on the electron = q(VxB)
= qvb sin
= 1.6*10^9*10^6* 0.5 * 10^-4 (sin 135)
=5.65*10^10 Newton along downward direction.
The ratio of this force to the weight of the electron = 5.65*10^10/1.672*10^-27 *9.8 =0.3448*10^37
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