A 50.0-kg woman stands at the rim of a horizontal turntable having a moment of i

Question

A 50.0-kg woman stands at the rim of a horizontal turntable having a moment of inertia of 520 kg · m2 and a radius of 2.00 m. The turntable is initially at rest and is free to rotate about a frictionless vertical axle through its center. The woman then starts walking around the rim clockwise (as viewed from above the system) at a constant speed of 1.50 m/s relative to the Earth.

With what angular speed does the turntable rotate?
_______ rad/s

(b) How much work does the woman do to set herself and the turntable into motion?
_______________

Explanation / Answer

The turntable rotates in the direction opposite to the direction the woman walks.

work done =

K = Kfinal - 0 = ½ mwoman vwoman² + ½ I table² = (0.5) (50) (1.5)² + (0.5) (520) (.288)² = 77.81 J

Hope that helps, let me know if you have any questions.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.