A block rests on a horizontal frictionless table. It is attached to a spring and
ID: 2028047 • Letter: A
Question
A block rests on a horizontal frictionless table. It is attached to a spring and set into motion. Consider what will happen to the frequency or period in each of the following situations.(Increase, Stay the same, Decrease)
If the mass of the block is cut in half, the period will _______.
(Increase, Stay the same, Decrease)
If the spring constant is cut in half (looser spring), the period will _______.
(Increase, Stay the same, Decrease)
If the mass of the block is doubled, the frequency will _______.
(Increase, Stay the same, Decrease)
If the spring constant is doubled (stiffer spring), the frequency will _______.
(Increase, Stay the same, Decrease)
If the amplitude of the motion is cut in half, the period will ______.
Explanation / Answer
A block rests on a horizontal frictionless table. It is attached to a spring and set into motion. Consider what will happen to the frequency or period in each of the following situations.
(Increase, Stay the same, Decrease)
As t=2*m/k
m is cut to half means T will decrease by 1/2 times
If the mass of the block is cut in half, the period will _Decrease______.
(Increase, Stay the same, Decrease)
As t=2*m/k
So if K is decrease to k/2 and t will increase
If the spring constant is cut in half (looser spring), the period will __Increase_____.
(Increase, Stay the same, Decrease)
t=2*m/k, and f=1/t
So m increased means t increases and f decreases
If the mass of the block is doubled, the frequency will __Decrease_____.
(Increase, Stay the same, Decrease)
t=2*m/k, and f=1/t
So if K is increased to 2k t will decrease so f increase
If the spring constant is doubled (stiffer spring), the frequency will _Increase______.
(Increase, Stay the same, Decrease)
t=2*m/k
Not dependent on Amplitude so remains same
If the amplitude of the motion is cut in half, the period will _Stay the same_____.
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