K21 of 21 In ne sixth episode of the television series Luke Cage, a character na

Question

K21 of 21 In ne sixth episode of the television series Luke Cage, a character named Claire Temple (played by Rosario Dawson) and a wounded detective are being pursued by hitmen. While Claire is helping the detective escape down an alleyway, a car comes hurtling toward them. Claire braces for impact and closes her eyes. She hears the sounds of a car crash in the distance. After opening her eyes, Claire sees the car wrapped around the title (played by Mike Colter). Luke managed to jump in front of the car before it reached Claire and, due to his superhuman strength general indestructableness, the car crashed into him as ifit crashed into a wall. Luke emerged from the crash unharmed.(The scene is featured all. Luke emerged from the crash unharmed. (The scene is featured in the first 8 seconds of the trailer for the first season) During the collision, Luke Cage does not appear to move at all. In other words, Luke does not slip backward. This makes you curious about the friction between the Luke and the road. . Based on the car's make, model, and speed before the crash, the momentum of the car during this scene can be modeled by the following equation: y(t) ( 2.15510x 104 kg * m/s )(1- ( 63 7829s l (1 1.02s ) +1) You look up the stats of the actor that plays Luke Cage (Mike Colter) and find out that he is 190.5 cm and 93 kg Part A t is necessary for Luke to remain stationary during the What is the minimum coefficient of static friction between Luke's boots and the road tha collision? Express your answer using 3 significant figures.

Explanation / Answer

part A:

let friction force =F

then change in momentum=impulse applied

==>F*time taken=change in momentum

==>F*8=(momentum at t=0)-(momentum at t=8 seconds)

==>F*8=21551-0=21551

==>F=2693.9 N

then friction coefficient=friction force/normal force

=2693.9/(mass*g)

=2693.9/(93*9.8)

=2.9558

hence friction coefficient of static friction is 2.9558.

in 3 signifcant figures, answer=2.96

part b:

as he is moving, kinetic friction will act.

kinetic friction=0.4*93*9.8=364.56 N

let time taken is t seconds.

then friction force*t=change in momentum

==>364.56*t=21551

==>t=59.115 seconds

in 3 significant figures, answer=59.1 seconds

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