23/2018 11:59 PM 70/100 Print CalculatorPerlodic Table 3/21/2018 05:15 PM Gr on

Question

23/2018 11:59 PM 70/100 Print CalculatorPerlodic Table 3/21/2018 05:15 PM Gr on 5 of 10 Sapling Learning Ma Each shot of the laser gun most favored by Rosa the Closer, the intrepid century, is powered by the discharge of a 191F capacitor charged to 58.5 kV. Rosa rightly reckons that of the lawless 22nd she can capacitor. This she would do by r possessing a dielectric constant of 935 the effect of each laser pulse by increasing the electric potential energy of the charged the capacitor's filling, whose dielectric constant is 419, with one Find the electric potential energy of the original capacitor when it is charged Number Calculate the electric potential energy of the upgraded capacitor when it is charged. Number O Previous Give Up & View Sciulicn 9Check Answer 0Next E int

Explanation / Answer

potential energy U = (1/2)*C1*V^2

C1 = capacitance = 1.91*10^-6 F

V = potential across capacitor = 58.5*10^3 V

U1 = (1/2)*1.91*10^-6*(58.5*10^3)^2

U1 = 3268.25 J

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capacitance without dielectric C = C1/k1

capacitance with dielectric K2 placed C2 = k2*C = C1*(K2/K1)

potential energy U2 = (1/2)*C2*V^2 = (1/2)C1*(k2/K1)*V^2

potential energy U2 = (K2/K1)*U1 = (935/419)*3268.25 = 7293.11 J

DONE please check the answer. any doubts post in comment box

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