11 1/2 points | Previous Answers SerCP11 19.P.009.MI. My Notes Ask Your Teacher

Question

11 1/2 points | Previous Answers SerCP11 19.P.009.MI. My Notes Ask Your Teacher A proton moving at 7.40 x 106 m s through a magnetic field of magnitude 1.74 T experiences a magnetic force of magnitude 7.80 3·What between the proton's velocity and the field? (Enter both possible answers from smallest to largest. Enter only positive values between O and 360.) smaller value 22.24 the angie larger value 02.24 Your response differs from the correct answer by more than 10%. Double check your calculations. Need Help? Read It Master it Master It 12. 1/2 points| Previous Answers SerCP11 19.P.008. My Notes Ask Your Teacher A potassium ion (K+) moves in the xy-plane with a speed of 2.40 x 103 m/s. If a constant magnetic field is directed along the z-axis with a magnitude of 1.50 x 10-5 T, find the magnitude of the magnetic force acting on the ion and the magnitude of the ion's acceleration. HINT (a) the magnitude (in N) of the magnetic force acting on the ion 5.766-21 where 8 is the angle between B and v. N The magnetic force has magnitude F = qvB only when the particle's velocity is perpendicular to the magnetic field. In general, F = qvBsin(0) (b) the magnitude (in m/s2) of the ion's acceleration m/s2 Watch t

Explanation / Answer

you have already calculated the smaller angle, larger angle is nothing but a 180-smaller angle

larger angle= 180-22.24= 157.76

b) F =ma

molecular weight of K+ = 39.098 g/mol, calculate the mass of poatsaaium ion and plug-in the following equation

you already have, , f , a= F/m

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