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1 pt A rectangular coil with 20 windings carries a current of 2.07 mA flowing in

ID: 2031086 • Letter: 1

Question

1 pt A rectangular coil with 20 windings carries a current of 2.07 mA flowing in the counterclockwise direction. It has two sides that are parallel to the y-axis and have length 8.31 cm and two sides that are parallel to the r-axis and have length 6.51 cm. A uniform magnetic field of 51.3 T acts in the positive z-direction. What torque must be applied to the loop to hold it steady? (in N*m) 11. AO 3.828 x 10 BO 4.479 x 10 CO 5.240x10-9 DO 6.131x io- EO 7.174 x 109 FO 8.393 x 10* GO 9.820 x 109 HO 1.149 x 108

Explanation / Answer

torque acting on a loop

T = BANi

here

B = 51.3*10^-6 T

A = 8.31*6.51*10^-4 = 54.09 *10^-4 m^2

T = 51.3*10^-6*54.09*10^-4*2.07*10^-3*20

T = 1.149*10^-8 Nm

option H