Pad :47 PM net Medicall Ilustrator I Lab 8- Mag Field a 9- Faraday\'s Law: Prela

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Pad :47 PM net Medicall Ilustrator I Lab 8- Mag Field a 9- Faraday's Law: Prelab Two Concentric Coils Of My eBooks Home My Assignments Grades PHY 2054L, section 012, Spring 2018 My Assignments Lab 9-Faraday's Law: Prelab (Lab9) Calendar Notiications Help My Options Juan Rivera PHY 2054L. section 012·Spring 2018 Instructor Nusaiba Zaman Current Score: 13.34 Due : Monday. March 26 2018 1200 AME Question -8.66 e.c4 66 6484.63 13.34 20104.7%) Points For this assignment, you submit answers by question parts. The number of submissions remaining for each question part only changes if you submit or change Your last submission is used for your scone My A single turn coil of radius 4.50 cm is held in a vertical plane and a magnet is rapidly moved relative to the coll as shown in the diagram below. coil The field inside the coil changes from 0.480 T to 0.285 T in 0.120 s. If the resistance of the coil is 3.90 , what are the magnitude and direction of the induced current in the coll as viewed from the side of the magnet? mA Tutorial Additional Materials Faraday's Law (Creating arent with Magnets) 2. .6/6.66 points 1 Previous Answers 19 PRE 002 My Two concentric coils of wire lie on a horizontal flat surface. The smaller coil is connected to a battery and a switch. The diagram shows the top view of the set up. coil 2 coil 1

Explanation / Answer

Given,

r = 4.5 cm = 0.045m ; B1 = 0.48 T ; B2 = 0.285 T ; t = 0.12 s ; R = 3.9 Ohm

We know that, due to change of magnetic flux through the coil, an emf will be induced,

emf = -d(phi)/dt = A dB/dt

emf = -A (B2 - B1)/t

emf = -3.14 x 0.045^2 (0.285 - 0.48)/0.12 = 0.0103 V

I = emf/R = 0.0103/3.9 = 0.0026 A

Hence, I = 0.0026 A = 2.6 x 10^-3 A = 2.6 milli A

Direction will be counterclockwise. Since the B field is into the left, the induced will be to the right.

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