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History Bookmarks People Window Help board.albany.edu/bbcswebdav/pid-2969925-dt-content-rid-18658587.1/courses/2183-APHY-109-S PRE-LAB QUESTIONS 1. Consider the circuit shown in Figure 6. a. If the resistance is 140 k and the capacitance is 15 F, what is the time constant? b. If the power supply voltage is 8 Volts, how long does it take the capacitor to charge to Ve 5 Volts? (See below for the algebra.) C. If a 50 F capacitor is placed in parallel to the first, what is the new time constant? d. If a 50 F capacitor is placed in series to the first, what is the new time constant? Rewriting Equation 2 to solve for time: v,.vt..(p))-H.(ic),÷,Waln(i-Y)--RC s Lecture Notes. - pLab 5 docx Bio335 Old Exam Qu... ppt 25

Explanation / Answer

Here ,

a) time constant , T = R * C

T = 140 *10^3 * 15 *10^-6

T = 2.1 s

the time constant is 2.1 s

b) Now , let the time taken is t

Vc = Vo * (1 - e^(-t/T))

5 = 8 * (1 - e^(-t/2.1))

solving for t

t = 2.06 s

the time taken is 2.06 s

c) for the capacitor to be connected in parallel

T = R * Ceq

T = 140 *10^3 * (15 *10^-6 + 50 *10^-6)

T = 9.1 s

the time constant is 9.1 s

d)

for the series capacitor

1/C1 = 1/15 + 1/50

C1 =11.54 uF

T = 140 *10^3 * 11.54 *10^-6

T = 1.61 s

the time constant is 1.61 s

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