2. A concave mirror (? 7.60 cm) and a convex mirror ( ,--640 cm are facing each

Question

2. A concave mirror (? 7.60 cm) and a convex mirror ( ,--640 cm are facing each other and are separated by a distance of 40.6 cm. An object is placed between the mirrors and is 20.3 cm from each mirror. Consider the light from the object that reflects first from the concave mirror and then from the convex mirror. What is the distance of the image (di2) produced by the convex mirror? 5.22 cm 3. The drawing shows a rectangular block of glass (n = 152) surrounded by liquid carbon disulfide (n = 1.66). A ray of light is incident on the glass at point A with a 01-21.0° angle of incidence. At what angle of refraction docs the ray leave the glass at point B? ×59.878]?

Explanation / Answer

2)

Use the mirror equation for the convex mirror: 1/o1 + 1/d1 = 1/(-6.40) with o1 = 20.3. Solve for d1: d1 = -4.87, i.e.

the image is behind the convex mirror. This image acts as an object for the concave mirror.

The object distance o2 = 40.6 + 4.87 (remember the image d1 is behind the convex mirror).

Now use the mirror equation for the concave mirror

1/o2 + 1/d2 = 1/7.60.

Solve for d2

d2 = 9.125 cm

3)  Let:
theta(1)=21 degrees
n=1.52
n1=1.66
Using SNELLS Law Take = n(1)sin*theta(1) = nsin*theta(2)

Solve for theta(2)  
theta (2) = 23 degrees

Let:
theta(2)= 23
theta (3) = 90-23 = 67 degrees
Solve for theta(4)?

nsin*theta(3) = n(1)sin*theta(4)  
theta(4) = 57.44 degrees

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