Part C: What is the magnetic flux through the loop at this angle? Constant Part

Question

Part C:

What is the magnetic flux through the loop at this angle?

Constant Part A A 12.andiamater circular loap of wires Rlaced n a 60." ? magnetic field hen the plane of the loop is perpendiculer to the lield lines, what is the magnede lux Uhrough the loop? Express your asweto two significant figures and include the appropriate units. Answer Requested Part B A u ? 1 The pare cf Ihe luup s rulated und il me kes a 35 angle wih lhe ield lines. Whal is ile angle in the equalion ?. Exprass your answer using rwo signlficant figuras. th situ tiun? Correct Part c hat is the magnetic lux trough the loop at this angle? Express your answeto two significant figures and include the appropeiate units

Explanation / Answer

(a) magnetic flux throught the loop = B.A? = B A cos(theta) = B A cos(00) = B A = 0.6 x pi x 0.062? = 0.00678 wb
?Here A is the area of the loop and B is the magnetic field. A = pi x r2 ; r = 0.06 m
?(b) field lines make (90 - theta) angle with the area vector i.e., theta is the angle between the area vector and the magnetic field. So, given the value of 90 - theta = 35.
Hence theta = 55 degrees.
?(c) magnetic flux throught the loop = B.A? = B A cos(theta) = B A cos(550) = 0.6 x pi x 0.062? x cos(55) = 0.00389 wb = 3.9 x 10-3 wb

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