AM radio wave, yellow light, X-ray, infrared light, green light, FM radio wave,

Question

AM radio wave, yellow light, X-ray, infrared light, green light, FM radio wave, gamma ray 5) Use the EM waves listed above to answer the following questions: a) Rank these electromagnetic waves on the basis of their speed in a vacuum from fastest to slowest. b) Rank these electromagnetic waves on the basis of their wavelength from longest to shortest. c) Rank these electromagnetic waves on the basis of their frequency from largest to smallest. d) Rank these electromagnetic waves on the basis of their energy from most to least.

Explanation / Answer

5a) In vacuum, all electromagnetic waves travel relatively at the same speed, which is equal to the speed of light (i.e., 3.0* (10)^8 metres/second). So, considering "Va"= Speed of AM radio wave, "Vy"= Speed of yellow light, "Vx"= Speed of X-ray, "Vi"= Speed of infrared light, "Vg"= Speed of green light, "Vf"= Speed of FM radio wave and "Vgr"= Speed of gamma ray, the rank will be as follows:

Va = Vy = Vx = Vi = Vg = Vf = Vgr = 3*(10^8)

5b) As per electromagnetic spectrum, radio waves have the maximum wavelength and gamma rays the minimum wavelength. In radio waves, AM radio waves have higher wavelength than that of FM radio waves due to modulation differences. X-rays have just higher wavelength than gamma rays. In visible light, as we move towards red light from violet light , the wavelengths increase in terms of VIBGYOR, where V = Violet, I = Indigo, B = Blue, G = Green, Y = Yellow, O = Orange and R = Red. So, considering  "La"= Wavelength of AM radio wave, "Ly"= Wavelength of yellow light, "Lx"= Wavelength of X-ray, "Li"= Wavelength of infrared light, "Lg"= Wavelength of green light, "Lf"= Wavelength of FM radio wave and "Lgr"= Wavelength of gamma ray, the rank will be as follows:

La>Lf>Li>Ly>Lg>Lx>Lgr

5c) Considering flow in vacuum, we have V = F * L , where V = speed of electromagnetic wave in vacuum (approximately = 3.0*(10^8) metres/sec) , F = frequency (in Hz) and L = wavelength (in metres). As per this condition, F ? (1/L). Hence the wave with the largest wavelength should have the smallest frequency and vice-versa. So, considering  "Fa"= Frequency of AM radio wave, "Fy"= Frequency of yellow light, "Fx"= Frequency of X-ray, "Fi"= Frequency of infrared light, "Fg"= Frequency of green light, "Ff"= Frequency of FM radio wave and "Fgr"= Frequency of gamma ray, the rank will be as follows:

Fgr>Fx>Fg>Fy>Fi>Ff>Fa

5d) Since energy associated with an electromagnetic wave is given as, E = h * F , where E = energy, h = Plank's constant (6.626 x 10-34 Js) and F = frequency (in Hz), hence order of energy will also be the same as that of frequency of the waves. Considering  "Ea"= Energy of AM radio wave, "Ey"= Energy of yellow light, "Ex"= Energy of X-ray, "Ei"= Energy of infrared light, "Eg"= Energy of green light, "Ef"= Energy of FM radio wave and "Egr"= Energy of gamma ray, the rank will be as follows:

Egr>Ex>Eg>Ey>Ei>Ef>Ea

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