You are stealing two priceless statues from a museum. You accomplish this by tyi

Question

You are stealing two priceless statues from a museum. You accomplish this by tying them with ropes as seen in the figure and dragging them. The statues are ALREADY IN MOTION. Statue 1 has a mass of 75 kg and a coefficient of kinetic friction of ?k = 0.15. Statue 2 has a mass of 120 kg and a coefficient of kinetic friction of ?k = 0.1. If you are pulling with a force of 460 N,

You are stealing two priceless statues from a museum. You accomplish this by tying them with ropes as seen in the figure and dragging them. The statues are ALREADY IN MOTION. Statue 1 has a mass of 75 kg and a coefficient of kinetic friction of ?k 0.15. Statue 2 has a mass of 120 kg and a coefficient of kinetic friction of uk 0.1. If you are pulling with a fqrce of 460N 3. (a) What is the acceleration of Statue 1? (b) What is the acceleration of Statue 2? (c) What is the tension in the rope between them? Statue sxMa

Explanation / Answer

Here the two masses move with same acceleration a1 = a2 = a

for statue 2

Fnet = m2*a

T - fk2 = m2*a

T - uk2*m2*g = m2*a

T = uk2*m2*g + m2*a .......(1)

for statue 1

Fnet = m1*a

F - T - fk1 = m1*a .............(2)

1 in 2

F - uk2*m2*g - m2*a - uk1*m1*g = m1*a

acceleration a = (F - uk2*m2*g - uk1*m1*g)/(m1+m2)

acceleration a = (460 - 0.1*120*9.8 - 0.15*75*9.8)/(75+120) = 1.19 m/s^2

a)

a1 = 1.19 m/s^2

b)

a2 = 1.19 m/s^2

c)

T = uk2*m2*g + m2*a

T = 0.1*120*9.8 + 120*1.19

T = 260.4 N = 260 N

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