(5%) Problem 16: A block of mass m-91 kg slides along a horizontal surface. The
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Question
(5%) Problem 16: A block of mass m-91 kg slides along a horizontal surface. The coefficient of friction between the block and the surface is u-0.38. The block has an initial speed of vo-12 m/s in the positive x-direction as shown Otheexpertta.com 33% Part (a) Write an expression for the x-component of the frictional force the block experiences, Ff, in terms of the given variables and variables available in the palette Grade Summary Deductions Potential 0% 100% Submissions Attempts remaining: 5 (10% per attempt) detailed view 0 Submit Hint Hints: 5% deduction per hint. Hints remaining: 3 Feedback: 0% deduction per feedback 33% Part (b) What is the magnitude of the frictional force in N? 33% Part (c) How far will the block travel, in meters, before coming to rest?Explanation / Answer
a) Ff = muk N
x-component of frictional force = -muk m g
b) Ff = 0.38 * 91 * 9.8
magnitude of frictional force = 338.9 N
c) a = F / m = 338.9 / 91 = 3.72 m/s2
distance x = 122 / (2 * 3.72)
= 19.33 m
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