clear work please Safari File Edit View History Bookmarks Window Help webassign.
ID: 2031707 • Letter: C
Question
clear work please
Safari File Edit View History Bookmarks Window Help webassign.net Submit Answer Save Progress points MI4 9.3.039 My Note You hold up an object that consists of two blocks at rest, each of mass M 5 kg, connected by a low-mass spring. Ther you suddenly start applying a larger upward force, of constant magnitude F 147 N (which is greater than 2Mg). The diagram shows the situation some time later, when the blocks have moved upward, and the spring stretch has increased. initially 2/ y1y Floor The heights of the centers of the two blocks are as follows Initial and final positions of block 1: Y -0.2 m, yr 0.3 m Initial and final positions of block 2: y2i 0.6 m, y2 0.9 m It helps to show these heights on a diagram. Note that the initial center of mass of the two blocks is ( Y2v2, and the final center of mass of the two blocks is (V22. (a) Consider the point particle system corresponding to the two blocks and the spring. Calculate the increase in the total translational kinetic energy of the two blocks. It is important to draw a diagram showing all of the forces that are acting and through what distance each force acts Increase in Ktrans (b) Consider the extended system corresponding to the two blocks and the spring. Calculate the increase of Kyb + Ug), the vibrational kinetic energy of the two blocks (their kinetic energy relative to the center of mass) plus the potential energy of the spring. It is important to draw a diagram showing all of the forces that are acting, and through what distance each force acts. Increase in (Kyib+ U)- Matarial 93Explanation / Answer
Given that,
m = 5 kg
F = 147 kg
(a)
Translational KE of two blocks,
KEt = (F - W) * [(y1f + y2f / 2) - (y1i + y2i / 2)]
KEt = (147 - 2*5*9.8) * [(0.3 + 0.9 / 2) - (0.2 + 0.6 / 2)]
KEt = 49 * 0.2
KEt = 9.8 J
(b)
lncrease in vibrational KE of blocks,
delta KEvib = F*(y2f - y2i) - 2*m*g*[(y1f + y2f / 2) - (y1i + y2i / 2)] - KEt
deltaKEvib = 147*(0.9 - 0.3) - 2*5*9.8*0.2 - 9.8
deltaKEvib = 58.8 J
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.