A 2000kg distance of 1.2km, the car\'s engine does 12,000 J the car after travel

Question

A 2000kg distance of 1.2km, the car's engine does 12,000 J the car after traveling the 1.2km? car drives along a horizontal road at an initial speed of 15m/s. While driving a of work on the car. What is the speed of 6. A skydiver will accelerate as the fall, obvious, but not forever; a skydiver will stop accelerating the terminal velocity for that skydiver. While the terminal velocity at a speed known as depends on things like the temperature and humidity of the air, the altitude of the sk and the surface area of the skydiver's body, it turns out to be roughly the same for all humans: about 50 m/s, while falling "spread eagle." Say a 65kg skydiver jumps out of an airplane and reaches terminal velocity after falling 450m-taking roughly 12s- how much work does air resistance do on the skydiver during this time? ydiver, 8. As a car's engine burns fuel, it produces work that drives the car forward. However, the work produced by the engine is produced on a part of the car known as the crankshaft. That energy has to be transferred from the engine to the wheels to drive the car forward. However machines are inherently inefficient, meaning that energy is lost as it is being transferred from one place to another due to friction in the parts. Say that a 2500kg car has an efficiency of 50%-that is, 50% of the work produced by the engine makes it to the wheels of the car. How much work does the engine need to produce in order to accelerate the car from rest to a speed of 20 m/s? 3. A 1200kg car moves with a velocity of 15m/s moving to the west when a 2500kg truck, moving to the east with a speed of 10m/s, collides into the car. If the wreckage sticks together, in what direction will the wreckage move? (a) East (b) West (c) It will be stationary (a) None of the above 4. Two masses, m -2kg and m2 1.3kg, collide head on. If my were moving at 10m/s, and m2 were moving at 15m/s, and the collision was elastic, what would be the speed of mo after the collision? If we said m? was initially moving to the left, in what direction would ma be moving after the collision?

Explanation / Answer

5. Initial KE + work done by car = Final KE of the car

mvi2/2 + 12000 = mvf2/2

2000 x 152/2 +12000 = 1000vf2

237000 = 1000vf2

vf = 15.4m/s

Hence the speed after driving 1.2 KM is 15.4 m/s

As per the chegg policy, we can answer only the first question in case of multiple questions. Please repost the other questions for their answer.

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.