Explore Two resistors R16.4 ? and R2-6.5 ? are connected in series and a potenti

Question

Explore Two resistors R16.4 ? and R2-6.5 ? are connected in series and a potential difference of ??, .. 12.0 V is imposed across them, as shown in the Active Figure. (A) Find the currents 11 and 12. (B) Find the equivalent resistance of the circuit 13.00 A resistance 10 resistance Conceptualize Use the circuit diagram shown in the Active Figure to visualize the situation. The battery maintains the same potential difference ?? across each resistor. The total current I must equal the sum of 11 and 12, and the relative size of 11 and 12 is determined by the relative values of the resistances 10 12-0.75 A AV AV2 | 6,00 V voltage 13.75 A 6 Req | 1.60 | 2 20 Display in a New Window Categorize We use the rules for resistors in parallel to determine the current and the voltage across each resistor

Explanation / Answer

I1 = 12/6.4 = 1.875 Amp

I2 = 12/6.5 = 1.846 Amp

I = I1 + I2 = 1.875 + 1.846 = 3.721 Amp

Req = 6.4*6.5/(6.4 + 6.5) = 3.224 ohm

Using Ohm's law:

V = I*Req

I = V/Req = 12/3.224 = 3.722 Amp

Yes these reasult are reasonable. And yes the value of the equivalent resistance give the total current.

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