20.1 A short circular coil with 15 turns has a radius of 7 cm. The coil is place
ID: 2032365 • Letter: 2
Question
20.1 A short circular coil with 15 turns has a radius of 7 cm. The coil is placed is a 2.5 T magnetic field. Find the flux through the coil for each case: a) the plane of the coil is perpendicular to the magnetic field b) the angle between the plane of the coil and the magnetic field is 35o.20.1 A short circular coil with 15 turns has a radius of 7 cm. The coil is placed is a 2.5 T magnetic field. Find the flux through the coil for each case: a) the plane of the coil is perpendicular to the magnetic field b) the angle between the plane of the coil and the magnetic field is 35o.
Explanation / Answer
here,
number of turns , N = 15 turns
radius ,r = 7 cm =0.07 m
magnetic feild , B = 2.5 T
a)
when the plane of the coil is perpendicular to the magnetic feild
the flux through the loop , phi = N * pi * r^2 * B
Phi = 15 * pi * 0.07^2 * 2.5 T.m^2
phi = 0.58 T.m^2
b)
theta = 35 degree
when the angle between the plane of the coil and the magnetic field is 35 degree
the flux through the loop , phi = N * pi * r^2 * B * sin(theta)
Phi = 15 * pi * 0.07^2 * 2.5 * sin(35) T.m^2
phi = 0.33 T.m^2
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