stan EXECUTE the solution as follows Learning Goal To practice Problem-Solving S

Question

stan EXECUTE the solution as follows Learning Goal To practice Problem-Solving Strategy 28.2 Ampere's Law Part C A solid cylindrical conductor is supported by insulating disks on the axis of a conducting tube with outer radius Ra 6.65 cm and inner radius R3.35 cm (Figure 1) The central conductor and the conducting tube carry equal currents of I 3.05 A in opposite directions. The currents are distributed uniformly over the cross sections of each conductor. What is the value of the magnetic field at a distance r = 4.76 cm from the axis of the conducting tube? What is the value of the magnetic field at a distance r = 4.76 cm from the axis of the conducting tube? Recall that Express your answer numerically in teslas. View Available Hint(s) Figure 1 of 1 B4.95 10-6 Submit Previous Ans X Incorrect; Try Again; 5 attempts remaining EVALUATE your answer Ra Part D This question will be shown after you complete previous question(s).

Explanation / Answer

Area enclosed by the cylinder is

pi*rout^2 - pi*rin^2 = pi(6.65^2 cm - 3.35^2 cm) = 0.010367 m^2

area of enclosec cylinder within 4.76 cm

A =  pi(4.76^2 cm - 3.35^2 cm) = 0.00359 m^2

current carried by the enclosed cylinder is

I1 =[ A / pi*rout^2 - pi*rin^2 ]*i

I1 = [0.00359 m^2 / 0.010367 m^2]3.05

I1 = 1.057 A

Net enclosed current is

I' = I - I1

I' = 1.993 A

magnetic field is

B = uoI' / 2pi*r

B = (4pi x 10^-7) / (2pi x 4.76 x 10^-2)

B = 4.2 x 10^-5 T

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